PNG General Mathematics Examination Question 41, 2011

If you're working with geometry problems involving squares and circles, understanding how to relate their measurements is key. In this example, we are given the area of a square and asked to find the radius of a circle perfectly inscribed within it. Follow the step-by-step solution below to learn how to solve such problems using basic algebra and geometry concepts.

Question: (Grade 12 General Mathematics Examination Question 41: 2011)

The diagram shows a circle inscribed in a square.


What is the radius of the circle if the area of the square is \(625 \, \text{cm}^2\)?


Solution:

Step 1: Understand the relationship
Since the circle is inscribed in the square, the diameter of the circle is equal to the side length of the square.

Step 2: Find the side length of the square
We are given:
\[ \text{Area of square} = \text{side}^2 \] \[ 625 = \text{side}^2 \] Take the square root of both sides: \[ \text{side} = \sqrt{625} = 25 \, \text{cm} \]

Step 3: Find the diameter of the circle
Since the circle fits exactly inside the square: \[ \text{Diameter of circle} = \text{side of square} = 25 \, \text{cm} \]

Step 4: Find the radius of the circle
\[ \text{Radius} = \frac{\text{Diameter}}{2} = \frac{25}{2} = 12.5 \, \text{cm} \]

Final Answer:

\[ \boxed{12.5 \, \text{cm}} \] Also check out
Previous Post Next Post

Advertisement